Educated guess: The same $\Gamma$-limit is obtained if $N_\varepsilon \to +\infty$ "slowly", i.e., $\theta_\varepsilon \to 0$ "slowly" as $\varepsilon \to 0$.
Question: Can we quantify the threshold rate $\text{?} \ll \theta_\varepsilon \ll 1$ as $\varepsilon \to 0$?
- $\displaystyle \frac{\theta_\varepsilon}{\varepsilon |\log \varepsilon|} \to +\infty \implies$ no information on $\displaystyle \frac{1}{\varepsilon^2 |\log \varepsilon|} E_\varepsilon(u_\varepsilon)$
- $\displaystyle \frac{\theta_\varepsilon}{\varepsilon |\log \varepsilon|} \to 0 \implies \frac{1}{\varepsilon^2 |\log \varepsilon|} E_\varepsilon(u_\varepsilon) \to 0 \implies $ no vortices
Conclusion: The $BV$-limit occurs if $\varepsilon |\log \varepsilon| \ll \theta_\varepsilon \ll 1$
$XY \text{?}$$\text{vortices?}$$BV$
$\varepsilon |\log \varepsilon|$
fastslow
---
## No vortices regime
Spin field: $u \colon \varepsilon \mathbb{Z}^2 \to \mathcal{S}_{N_\varepsilon}$, with $N_\varepsilon \to +\infty$, i.e., $\theta_\varepsilon \to 0$
Constraint: $\displaystyle \theta_\varepsilon \ll \varepsilon |\log \varepsilon| \implies \frac{1}{\varepsilon^2 |\log \varepsilon|} E_\varepsilon(u_\varepsilon) \to 0 \implies $ no vortices
A Lavrentiev gap?
For $u_\varepsilon \to u$ in $L^1(\Omega;\mathbb{S}^1)$, do we expect this strict inequality?
\\[
\liminf_{\varepsilon \to 0} \frac{1}{\varepsilon \theta_\varepsilon} E_\varepsilon(u_\varepsilon) > \int_\{\Omega\} |\nabla u|_\{2,1\} \\, \mathrm{d} x + |\mathrm{D}^\{(c)\} u|_\{2,1\}(\Omega) + \int_\{J_u\} \mathrm{d}_\{\mathbb{S}^1\}(u^-,u^+) |\nu_u|_1 \\, \mathrm{d} \mathcal{H}^1
\\]
--
## Back to the original problem
Spoiler alert: [Yes](#/back-to-original-problem)
---
## An analogous problem in the smooth setting
Problem: Relax
\\[
\int_{\Omega} |\nabla u| \\, \mathrm{d} x \\, , \quad u \in C^\infty(\Omega;\mathbb{S}^1)
\\]
- Giaquinta, Modica, Souček. Calc. Var. PDEs (1993)
Facts:
- The relaxation domain is $BV(\Omega;\mathbb{S}^1)$
- $\displaystyle \frac{x}{|x|} \in W^{1,p}(B_1;\mathbb{S}^1)$ for $p \in [1,2)$, hence it is in the relaxation domain
- $\displaystyle \mathrm{deg}\Big( \frac{x}{|x|}, \partial B_\rho \Big) = 1$, for every $\rho \in (0,1)$
- $u \in C^\infty(B_1;\mathbb{S}^1) \implies \mathrm{deg}\big( u, \partial B_\rho \big) = 0$, for every $\rho \in (0,1)$
- Topological obstruction: $\nexists \\, u_\varepsilon \in C^{\infty}(B_1;\mathbb{S}^1)$ such that $u_\varepsilon \stackrel{\text{stricly-}BV}{\longrightarrow} \frac{x}{|x|}$
---
## Approximating singularities with smooth maps
Aim: Approximate $\displaystyle \frac{x}{|x|}$ via $C^{\infty}(\Omega;\mathbb{S}^1)$ maps and minimal energy $\displaystyle \int_\Omega |\nabla u| \mathrm{d}x$
$u = e^{\iota 2 \pi \varphi}$
$\varphi$
Fact 1: If $u \in C^\infty(\Omega;\mathbb{S}^1)$, then $G_u$ has no boundary
Fact 2: The graph $G_{\frac{x}{|x|}}$ has boundary $-\delta_0 \times \llbracket \mathbb{S}^1 \rrbracket$
(Compactness): $\hspace{2em} G_{u_\varepsilon} \rightharpoonup T$ and $T \in \mathrm{cart}(\Omega \times \mathbb{S}^1)$
($\Gamma$-liminf): $\hspace{4.2em} \displaystyle \liminf_{\varepsilon \to 0}\int_\Omega |\nabla u_\varepsilon| \\, \mathrm{d} x \geq \int_\{\Omega \times \mathbb{R}^2\} \Phi(\vec T)\\, \mathrm{d} |T|$
($\Gamma$-limsup): $\hspace{3.5em}$ Given $T \in \mathrm{cart}(\Omega \times \mathbb{S}^1)$, $\exists \\, u_\varepsilon$ such that $G_{u_\varepsilon} \rightharpoonup T$ and $\hspace{8.3em} \displaystyle \lim_{\varepsilon \to 0}\int_\Omega |\nabla u_\varepsilon| \\, \mathrm{d} x = \int_\{\Omega \times \mathbb{R}^2\} \Phi(\vec T)\\, \mathrm{d} |T|$
$\hspace{8em}$ Giaquinta, Modica, Souček. Calc. Var. PDEs (1993)
Note: If $u_\varepsilon \stackrel{\*}{\rightharpoonup} u$, then, in general, $T \neq G_u$
---
## Structure theorem
Theorem [Giaquinta, Modica, Souček - Calc. Var. PDEs (1993)]
1. Let $T \in \mathrm{cart}(\Omega \times \mathbb{S}^1)$. Then there exist:
- a unique $u_T \in BV(\Omega;\mathbb{S}^1)$;
- an i.m. rectifiable 1-current $L \in \mathcal{D}_1(\Omega)$ such that $T = G_\{u_T\} + L \times \llbracket \mathbb{S}^1 \rrbracket$.
2. Given $u \in BV(\Omega;\mathbb{S}^1)$, there exists $T \in \mathrm{cart}(\Omega \times \mathbb{S}^1)$ such that $u = u_T$.
--
## Lifting in $BV$
Strictly related to the problem of lifting $BV$ functions with values in $\mathbb{S}^1$
- Dávila, Ignat. C. R. Acad. Sci. Paris, Ser. I (2003)
- Ignat. Ann. Inst. H. Poincaré Anal. Non Linéaire (2005)
- Canevari, Orlandi. J. Funct. Anal. (2020)
---
## An analogous problem in the smooth setting
Theorem [Giaquinta, Modica, Souček - Calc. Var. PDEs (1993)]
$\displaystyle \hspace{1.5em} \int_\Omega |\nabla u| \\, \mathrm{d} x \hspace{0em} \stackrel{\Gamma}{\rightarrow} \hspace{0em} \int_{\Omega \times \mathbb{R}^2} \Phi(\vec T) \\, \mathrm{d} |T| = \int_\Omega |\nabla u| \\, \mathrm{d} x + |\mathrm{D}^{\text{(c)}}u|(\Omega) + \mathcal{J}(u;\Omega)$
$\displaystyle \hspace{0em} \big(u \in C^\infty(\Omega;\mathbb{S}^1)\big) \hspace{12.5em} \big( u \in BV(\Omega;\mathbb{S}^1)\big)$
where $\displaystyle \mathcal{J}(u;\Omega) = \inf_{T \in \mathrm{cart}(\Omega \times \mathbb{S}^1)} \Big\\{ \int_{J_T} \ell_T(x) \mathrm{d} \mathcal{H}^1(x) : T = G_u + L \times \llbracket \mathbb{S}^1 \rrbracket \Big\\}$.
--
## Not subadditive
$\displaystyle E\Big(\frac{x}{|x|};B_{R}\Big) = \int_{B_{R}} \Big| \nabla \frac{x}{|x|} \Big| \, \mathrm{d} x + 2 \pi R = 2 \pi R + 2 \pi R = 4 \pi R$